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=7Y^2-2Y-1
We move all terms to the left:
-(7Y^2-2Y-1)=0
We get rid of parentheses
-7Y^2+2Y+1=0
a = -7; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·(-7)·1
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4\sqrt{2}}{2*-7}=\frac{-2-4\sqrt{2}}{-14} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4\sqrt{2}}{2*-7}=\frac{-2+4\sqrt{2}}{-14} $
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